[Skip Breadcrumb Navigation]
:
[Skip Breadcrumb Navigation]
Home
Chapter 8: Aromaticity - Reactions of Benzene and Substituted Benzenes
Quizzes
Quiz 1
Quiz 1
This activity contains 15 questions.
In what orbitals are the lone pairs of electrons on the oxygen atom in furan?
p
and
p
sp
2
and
sp
2
s
and
p
sp
and
p
sp
2
and
p
For a compound to be aromatic, how many pi electrons must be in the pi cloud?
an odd number of pairs
an odd number
an even number
at least three pairs
an even number of pairs
Which of the following molecules is
not
aromatic?
thiophene
pyrrole
cycloheptatrienyl cation
cyclopentadiene
furan
Which series of reactions would give 1-phenylbutane as the major product?
1-chlorobutane + benzene + AlCl
3
1) butanoyl chloride + benzene 2) Zn + HCl
1) butanoyl chloride + benzene + AlCl
3
2) Zn + HCl
butanoyl chloride + benzene + AlCl
3
What purpose does sulfuric acid play in the nitration of benzene?
It protonates the benzene ring.
It protonates nitric acid, which leads to loss of water and formation of the nitronium ion.
It produces HSO
3
+
.
It accepts a proton from nitric acid.
It is the solvent.
For which set of conditions would a Friedel–Crafts alkylation of benzene
not
occur?
1-chlorobutane + AlCl
3
propene + HF
propane + AlCl
3
2-chloro-2-methylpropane + AlCl
3
How many pi electrons are there in purine?
6
8
10
12
14
Which of the following is
not
required for a molecule to be aromatic?
The molecule must have 4
n
+ 2 pi electrons.
The molecule must be flat.
The molecule must be cyclic.
All of the atoms must be
sp
hybridized.
Every atom on the ring must have a
p
orbital.
How many ring atoms have a partial positive charge in the carbocation intermediate that is formed in an electrophilic aromatic substitution reaction of benzene?
1
2
3
4
6
What is the hybridization of the oxygen in furan?
sp
3
s
sp
p
sp
2
What role does the Fe(III) halide play in the halogenation of aromatic compounds with Cl
2
or Br
2
?
It is the source of Br or Cl in the reaction.
It forms a carbocationic intermediate with benzene.
It forms a bromine radical.
It abstracts a bromine or chlorine atom to give the electrophilic Br
+
or Cl
+
.
It acts as a nucleophile to give chloride or bromide anions.
Why must more than one equivalent of AlCl
3
be used in the Friedel–Crafts acylation of benzene?
Acid chlorides are not very reactive towards AlCl
3
.
because two equivalents of AlCl
3
are required to remove chloride from an acid chloride
because AlCl
3
forms a stable complex with the ketone product of the acylation
because AlCl
4
–
will not remove H
+
in the last step of the mechanism
to form a carbocation intermediate with the benzene ring
Which of the following would
not
give 2-phenylbutane as the major product in a Friedel–Crafts alkylation reaction?
1-butene + HF
2-chlorobutane
1) butanoyl chloride + AlCl
3
2) Zn, HCl
2-butanol + H
2
SO
4
butyl chloride + AlCl
3
What is formed when acetic anhydride is reacted with AlCl
3
?
CH
3
CO
+
+ AlCl
4
–
CH
3
CO-AlCl
3
–
+ CH
3
C(O)-O
+
CH
3
CO
+
+ CH
3
C(O)-O-AlCl
3
–
no reaction
CH
3
CO-AlCl
2
+ CH
3
C(O)Cl
Which of the following is
not
true about electrophilic substitution reactions?
The product of an electrophilic aromatic substitution is not aromatic.
Other than the structure of the electrophile, all electrophilic substitutions have the same mechanism.
The carbocation intermediate is resonance stabilized.
The proton removed from the ring comes from the carbon where the electrophile was added.
The rate-limiting step is always electrophile addition to the aromatic ring.
The Clear Answers feature requires scripting to function. Your browser either does not support scripting or you have turned scripting off. So, the Clear Answers feature will not work. Note that you do not need to use the Clear Answers feature in order to use this site. You can change your answers for each question individually.
Your browser either does not support scripting or you have turned scripting off. Because of this, the answer choices will NOT appear in a different order each time the page is loaded, though that is mentioned below. Note that you do not need this feature to use this site.
Answer choices in this exercise appear in a different order each time the page
is loaded.
Copyright © 1995 - 2021
Pearson Education
. All rights reserved. Pearson Prentice Hall is an imprint of
Pearson
.
Legal Notice
|
Privacy Policy
|
Permissions
[Return to the Top of this Page]
: return
