Suppose you are setting up a reaction that requires an iodide salt and are planning to use sodium iodide. However, at the last minute you find that you are out of sodium iodide, so you must use potassium iodide instead. Will you need to weigh out more, less, or the same mass of potassium iodide in order to get the same number of moles of iodide ions?
Li + N2 Li3N
Mg3N2 + H2O Mg(OH)2 + NH3
Gaseous hydrogen reacts with carbon monoxide to form methanol, CH3OH.
AgNO3 + AlCl3 Al(NO3)3 + AgCl