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Chapter 6
Multiple Choice
Multiple Choice
From the choices below these questions or statements choose the correct answer to the question, identify the statement as true or false, choose the words that correctly fill in the blanks, or choose the phrase that correctly completes the statement.
This activity contains 31 questions.
For the common-emitter amplifier ac equivalent circuit, all capacitors are
effectively shorts.
effectively open circuits.
not connected to ground.
connected to ground.
For a common-emitter amplifier, the purpose of the emitter bypass capacitor is
no purpose, since it is shorted out by R
E
.
to reduce noise.
to despike the supply voltage.
to maximize amplifier gain.
For a common-emitter amplifier, the purpose of swamping is
to minimize gain.
to reduce the effects of r'
e
to maximize gain.
no purpose.
An emitter-follower is also known as a
common-emitter amplifier.
common-base amplifier.
common-collector amplifier.
Darlington pair.
In a common-base amplifier, the input signal is connected to the
base.
collector.
emitter.
output.
The differential amplifier produces outputs that are
common mode.
in-phase with the input voltages.
the sum of the two input voltages.
the difference of the two input voltages.
The differential amplifier has
one input and one output.
two inputs and two outputs.
two inputs and one output.
one input and two outputs.
The dc emitter current of a transistor is 8 mA. What is the value of r
e
?
320
13.3 k
3.125
5.75
Refer to Figure 6-1. Calculate the value of V
B
.
Figure 6-1
5 V
3.7 V
20 V
3 V
Refer to Figure 6-1. Find the value of I
E
.
2 mA
4 mA
5 mA
6 mA
Refer to Figure 6-1. Determine the value of V
C
.
20 V
10 V
5 V
0 V
Refer to Figure 6-1. Find the value of R
in(base)
.
420
50 k
940
100.8
Refer to Figure 6-1. Calculate the value of R
in(tot)
.
37.7 k
3.77 k
378
2.25 k
Refer to Figure 6-1. Determine the value of A
v
.
49.6
5
100
595
Refer to Figure 6-1. If an emitter bypass capacitor was installed, determine the value of R
in(base)
.
416
5 k
50 k
500
Refer to Figure 6-1. If an emitter bypass capacitor was installed, calculate the value of R
in(tot)
.
378
420
500
40 k
Refer to Figure 6-1. If an emitter bypass capacitor was installed, what would the new A
v
be?
4.96
125
398
600
An emitter-follower amplifier has an input impedance of 107 k
. The input signal is 12 mV. The approximate output voltage is (common-collector)
8.92 V
112 mV
12 mV
8.9 mV
Refer to Figure 6-2. You notice while servicing this amplifier that the output signal at V
out
is reduced from normal. The problem could be caused by
Figure 6-2
an open C
3
.
an open C
2
.
an open base-emitter of Q
2
.
a shorted C
2
.
Refer to Figure 6-2. The output signal from the first stage of this amplifier is 0 V. The trouble could be caused by
an open C
4
.
an open C
2
.
an open base-emitter of Q
1
.
a shorted C
4
.
A Darlington pair amplifier has
high input impedance and high voltage gain.
low input impedance and low voltage gain.
a voltage gain of about 1 and a low input impedance.
a low voltage gain and a high input impedance.
You have a need to apply an amplifier with a very high power gain. Which of the following would you choose?
common-collector
common-base
common-emitter
emitter-follower
What is the most important r parameter for amplifier analysis?
r
b
′
r
c
′
r
e
′
A common-emitter amplifier has _____ voltage gain, _____ current gain, _____ power gain, and _____ input impedance.
high, low, high, low
high, high, high, low
high, high, high, high
low, low, low, high
To analyze the common-emitter amplifier, what must be done to determine the dc equivalent circuit?
leave circuit unchanged
replace coupling and bypass capacitors with opens
replace coupling and bypass capacitors with shorts
replace V
CC
with ground
When the bypass capacitor is removed from a common-emitter amplifier, the voltage gain
increases.
decreases.
has very little effect.
A common-collector amplifier has _____ input resistance, _____ current gain, and _____ voltage gain.
high, high, low
high, low, low
high, low, high
A Darlington pair provides beta _____ for _____ input resistance.
multiplication, decreased
multiplication, increased
division, decreased
The total gain of a multistage amplifier is the _____.
sum of individual voltage gains
sum of dB voltage gains
What is r
e
equal to in terms of h parameters?
h
re
/ h
oe
(h
re
+ 1) / h
oe
h
ie
– (h
re
/ h
oe
)(1 + h
fe
)
h
fe
none of the above
The advantage that a Sziklai pair has over a Darlington pair is
higher current gain.
less input voltage is needed to turn it on.
higher input impedance.
higher voltage gain.
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